Math - Find the constant k so that the quadratic equation 2x2 + 5x - k = 0 has two real solutions.

Best Answer: (x,y) (-2,-3) (-1,-4) (0,-3) (1,0) (2,5) Just substitute your x values into the equation and plug the whole thing into your calculator. Or, if ...

(x+1)^2=9 5. x^2-2x-5=0 6. 3x^2+x-1=0 For 7-10, if a quadratic equation with integral ... For 14 and 15, pick the correct description of the roots of the equations ...

2x^2-5x=1 The given equation is a quadratic equation. There are two values of variable x. 2x2 - 5x - 1 =0 The values of x can be calculated by using quadratic formula.

This quadratic equation which will have two solutions can be solved by completing the square or by using the quadratic equation formula. Completing the square: x 2 ...

4y 2 + 6y + 2y + 3 = 0 [4] Now put the terms into groups of two : blank ( 4y 2 + 6y ) + ( 2y + 3 )= 0 ... [7] now since 2y+3 is a common factor of the terms on ...

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